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Engine efficiency=output/input
If the engine output is raised, say by enabling it to rev to a higher rpm, and at the same time the input is reduced in the process of doing that, won't the efficiency be doubly raised? In an automotive world where more power is normally possible only by increasing the fuel input, can this be possible?
The answer is yes! Using a Surbo, you will not need to press more on the accelerator to get more power, but you press less to get more power! The reason is related to how the Surbo is activated (see How It Works), with a relatively-closed throttle generating a back pressure at the Surbo, causing the Surbo to spin the air at high speed and creating a vortex, which raises air compression. Recall that the way to increase efficiency in an engine is to raise its compression. However, there might be a practical limit to increasing the engine compression in petrol engines, lest it results in knocking (over-compression in a petrol engine results in spontaneous firing before the spark plug is ignited). However, the Surbo is known to have most of its power at minus 8mmHg manifold vacuum (see How It Works or the Boost Gauge page), which is below the detonation threshold. In actual use, the Surbo is normally observed to bring the engine to the rpm red line with just half throttle (smaller input). If the rpm was delimited, the increase in output will be even higher, and the efficiency of the engine raised so much more.
Mathematically, since the throttle is pressed less to generate this air compression raising vortex, the denominator in the equation is also lessened as the fuel input is less. Therefore, the Surbo raises engine efficiency. This means that there will be extra energy for every bit of fuel you put in, that will be translated to extra speed or mileage.
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